x(4x+7)-(4x^2+5x+4)=4

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Solution for x(4x+7)-(4x^2+5x+4)=4 equation:


Simplifying
x(4x + 7) + -1(4x2 + 5x + 4) = 4

Reorder the terms:
x(7 + 4x) + -1(4x2 + 5x + 4) = 4
(7 * x + 4x * x) + -1(4x2 + 5x + 4) = 4
(7x + 4x2) + -1(4x2 + 5x + 4) = 4

Reorder the terms:
7x + 4x2 + -1(4 + 5x + 4x2) = 4
7x + 4x2 + (4 * -1 + 5x * -1 + 4x2 * -1) = 4
7x + 4x2 + (-4 + -5x + -4x2) = 4

Reorder the terms:
-4 + 7x + -5x + 4x2 + -4x2 = 4

Combine like terms: 7x + -5x = 2x
-4 + 2x + 4x2 + -4x2 = 4

Combine like terms: 4x2 + -4x2 = 0
-4 + 2x + 0 = 4
-4 + 2x = 4

Solving
-4 + 2x = 4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 2x = 4 + 4

Combine like terms: -4 + 4 = 0
0 + 2x = 4 + 4
2x = 4 + 4

Combine like terms: 4 + 4 = 8
2x = 8

Divide each side by '2'.
x = 4

Simplifying
x = 4

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